**Calculate the mass of fine particles inhaled by an adult each year.? - index.of adult and magazine**

Assuming he / she breathes approximately 350L of air per hour and the average of the PM2.5 air is about 10 mg / m 3 ^ Assuming that each of these particles have a diameter of about 1 micron and the particle density is about 0.5g/mL, the calculation of the annual burden of this particle.

Note: The surface of a spherical particle is equal 4Πr ^ 2, where r is the radius.

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The total volume of air per year

V_air = 0.350 m ³ / h 24 h / d • 365d

= 3066m ³

The total mass of solids inhalation

= C_solid m_solid · V_air

= 10 micrograms / m³ · 3066m ³

= 0.03066g

The volume of a particle

V_P = (4 / 3) π · r_p ³ ·

Bulk

Ρ = M_P _p _p · V_P = ρ * (4 / 3) π · r_p ³ ·

and its surface

S_p = 4 π ² · r_p ·

So its surface. This means that the area per unit mass:

= S_P s_p / M_P

= 3 / (ρ _p · rp)

= 3 / (· 0.5g/mL 1 micrometer) = 3 / (5 × 10 ^ 5 g / m³ · 1 × 10 ^-6m)

= 6 m² / g

The specific surface area of the entire solid is the same as for a single particle. Therefore

S_solid = s_solid · m_solid = s_p · m_solid

= 6 m² / g ⋅ 0.03066g

= 0.18396m ²

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