Calculate the mass of fine particles inhaled by an adult each year.? - index.of adult and magazine
Assuming he / she breathes approximately 350L of air per hour and the average of the PM2.5 air is about 10 mg / m 3 ^ Assuming that each of these particles have a diameter of about 1 micron and the particle density is about 0.5g/mL, the calculation of the annual burden of this particle.
Note: The surface of a spherical particle is equal 4Πr ^ 2, where r is the radius.
The total volume of air per year
ReplyDeleteV_air = 0.350 m ³ / h 24 h / d • 365d
= 3066m ³
The total mass of solids inhalation
= C_solid m_solid · V_air
= 10 micrograms / m³ · 3066m ³
= 0.03066g
The volume of a particle
V_P = (4 / 3) π · r_p ³ ·
Bulk
Ρ = M_P _p _p · V_P = ρ * (4 / 3) π · r_p ³ ·
and its surface
S_p = 4 π ² · r_p ·
So its surface. This means that the area per unit mass:
= S_P s_p / M_P
= 3 / (ρ _p · rp)
= 3 / (· 0.5g/mL 1 micrometer) = 3 / (5 × 10 ^ 5 g / m³ · 1 × 10 ^-6m)
= 6 m² / g
The specific surface area of the entire solid is the same as for a single particle. Therefore
S_solid = s_solid · m_solid = s_p · m_solid
= 6 m² / g ⋅ 0.03066g
= 0.18396m ²